Answer by Thiago Navarro for switch-case statement without break

Try yourself - Run the code using ideone available here.

#include <stdio.h>void doA(int *i){    printf("doA i = %d\n", *i);    *i = 3;}void doB(int *i){    printf("doB i = %d\n", *i);    *i = 4;}void doC(int *i){    printf("doC i = %d\n", *i);    *i = 5;}int main(void) {    int i = 1;    switch(i){        case 1:            doA(&i);        case 2:            doB(&i);        default:            doC(&i);            break;    }    return 0;}

Output:

doA i = 1doB i = 3doC i = 4

Note:

• It will execute all the options from the selected case until it sees a break or the switch statement ends. So it might be that only C is executed, or B and then C, or A and B and C, but never A and C
• If you change the value of the variable analysed in switch inside the handle function (e.g doA), it does not affect the flow as describe above